Question

An open lift is moving upwards with velocity 10 m/s. It has an upward acceleration of 2 m/s2. A ball is projected upwards with velocity 20 m/s relative to ground. Find the time when ball again meets the lift.

- 54 s
- None
- 43 s
- 53 s

Solution

The correct option is **D** 53 s

At the time when ball again meets the lift, sL=sB

∴10t+12×2×t2=20t−12×10t2

Solving this equation, we get

∴ Ball will again meet the lift after 53 s.

At the time when ball again meets the lift, sL=sB

∴10t+12×2×t2=20t−12×10t2

Solving this equation, we get

∴ Ball will again meet the lift after 53 s.

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